Question 1Data and SQL
Write a query that finds each customer's first and most recent order.
A quick check that you're comfortable with grouping, joins and window functions.
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The answerFour steps
- 1
Clarify the tables and what counts as an order (cancelled ones?)
Say it like this
“First I'd ask what counts as an order: do cancelled or refunded ones count, and is created_at in UTC?”
Why it scores
Pins down the definition before the syntax. Cancelled orders change the answer.
- 2
Use MIN/MAX with GROUP BY, or ROW_NUMBER() if you need the whole row
Say it like this
“If they only need dates, it's one pass:
MIN(created_at)andMAX(created_at)withGROUP BY customer_id. If they want the whole row, like the amount of the first order, I'd useROW_NUMBER() OVER (PARTITION BY customer_id ORDER BY created_at), once ascending and once descending, and keep row 1 of each.”Why it scores
Knows when the simple version is enough and when you need the whole row.
- 3
Handle ties on the same timestamp, and customers with no orders
Say it like this
“Two orders can share a timestamp, so I add order_id to the ORDER BY to make it deterministic. Customers with no orders only show up if I start from customers with a LEFT JOIN.”
Why it scores
Ties and missing customers are the bugs interviewers wait for.
- 4
Explain how you'd test it on a few known customers
Say it like this
“Then I pick three customers to check by hand: one with a single order, one with 40, one whose first order was cancelled.”
Why it scores
Tests on cases chosen to break it, not on whatever comes back first.
StrongAll together
About a minute, out loud. The marked parts are the four steps; hover one to find it above.
First I'd ask what counts as an order: do cancelled or refunded ones count, and is created_at in UTC?1 Say we exclude cancelled. If they only need dates, it's one pass: MIN(created_at) and MAX(created_at) with GROUP BY customer_id. If they want the whole row, like the amount of the first order, I'd use ROW_NUMBER() OVER (PARTITION BY customer_id ORDER BY created_at), once ascending and once descending, and keep row 1 of each.2 Two orders can share a timestamp, so I add order_id to the ORDER BY to make it deterministic. Customers with no orders only show up if I start from customers with a LEFT JOIN.3 Then I pick three customers to check by hand: one with a single order, one with 40, one whose first order was cancelled.4
WeakThe answer that fails
Sounds fine. Common. Scores low.
“I'd group by customer_id and take MIN and MAX of order_date. If they need the other columns, I'd join the orders table back on customer_id and that date to get the full row.”
Interviewer's note
Joining back on a date duplicates rows when two orders share it. Never asked what counts as an order, never tested.
PracticeTwo minutes, then they push back
Your turn
Write a query that finds each customer's first and most recent order.
Answer like you're in the room: about two minutes, no notes. Say it out loud, even alone. It feels different from thinking it. Then check your answer against what interviewers score.